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# -*- coding: UTF-8 -*-
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"""Directed graph production.
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This module contains the code to produce an ordered directed graph of a
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bzr branch, such as we display in the tree view at the top of the bzrk
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__copyright__ = "Copyright © 2005 Canonical Ltd."
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__author__ = "Scott James Remnant <scott@ubuntu.com>"
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from bzrlib.errors import NoSuchRevision
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class DummyRevision(object):
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"""Dummy bzr revision.
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Sometimes, especially in older bzr branches, a revision is referenced
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as the parent of another but not actually present in the branch's store.
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When this happens we use an instance of this class instead of the real
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Revision object (which we can't get).
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def __init__(self, revid):
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self.revision_id = revid
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self.message = self.revision_id
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def graph(branch, start):
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"""Produce a directed graph of a bzr branch.
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Traverses the branch revision tree starting at start and produces an
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ordered list of revisions such that a revision always comes after
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any revision it is the parent of. It also tries to make a reasonably
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not-too-stupid decision whether a parent revision is on the same
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logical branch, as that information is not available with bzr.
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For each revision it then yields a tuple of (revision, node, lines).
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If the revision is only referenced in the branch and not present in the
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store, revision will be a DummyRevision object, otherwise it is the bzr
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Revision object with the meta-data for the revision.
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Node is a tuple of (column, colour) with column being a zero-indexed
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column number of the graph that this revision represents and colour
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being a zero-indexed colour (which doesn't specify any actual colour
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in particular) to draw the node in.
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Lines is a list of tuples which represent lines you should draw away
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from the revision, if you also need to draw lines into the revision
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you should use the lines list from the previous iteration. Each
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typle in the list is in the form (start, end, colour) with start and
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end being zero-indexed column numbers and colour as in node.
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It's up to you how to actually draw the nodes and lines (straight,
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curved, kinked, etc.) and to pick the actual colours for each index.
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revisions = { start: branch.get_revision(start) }
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distances = { start: 0 }
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colours = { start: 0 }
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# Sort the revisions; the fastest way to do this is to visit each node
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# as few times as possible (by keeping the todo list in a set) and record
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# the largest distance to it before queuing up the children if we
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# increased the distance. This produces the sort order we desire
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revision = revisions[revid]
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distance = distances[revid] + 1
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colour = colours[revid]
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for parent_id in revision.parent_ids:
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# Check whether there's any point re-processing this
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if parent_id in distances and distances[parent_id] >= distance:
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# Get the parent from the cache, or put it in the cache
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parent = revisions[parent_id]
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parent = revisions[parent_id] \
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= branch.get_revision(parent_id)
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except NoSuchRevision:
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parent = revisions[parent_id] = DummyRevision(parent_id)
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# Make a guess as to whether this node represents the same
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# branch, or a new one. Penalise same branches in the distance
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# stakes to give new ones a chance to appear first as one set.
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if len(revision.parent_ids) == 1:
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colours[parent_id] = colour
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distances[parent_id] = distance
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elif revision.committer == parent.committer and not reused:
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colours[parent_id] = colour
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distances[parent_id] = distance
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colours[parent_id] = last_colour = last_colour + 1
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distances[parent_id] = distance + 10
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# Now iterate the revisions again, but this time in list order rather
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# than traversing the tree, and build up the graph lines. We do this
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# by keeping a list of "hanging parents", which can only be removed
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# once we encounter the revision being hung.
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for revid in sorted(distances, key=distances.get):
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for h_idx, hang in enumerate(hanging):
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# We've matched a hanging revision, so need to output a node
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node = (h_idx, colours[revid])
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# Now we need to hang its parents, we put them at the point
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# the old column was so anything to the right of this has
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# to move outwards to make room. We also try and collapse
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# hangs to keep the graph small.
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for parent_id in revisions[revid].parent_ids:
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n_idx = new_hanging.index(parent_id)
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n_idx = len(new_hanging)
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new_hanging.append(parent_id)
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lines.append((h_idx, n_idx, colours[parent_id]))
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# Revision keeps on hanging, adjust for any change in the
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# graph shape and try to collapse hangs to keep the graph
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n_idx = new_hanging.index(hang)
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n_idx = len(new_hanging)
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new_hanging.append(hang)
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lines.append((h_idx, n_idx, colours[hang]))
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hanging = new_hanging
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yield (revisions[revid], node, lines)
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# -*- coding: UTF-8 -*-
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"""Directed graph production.
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This module contains the code to produce an ordered directed graph of a
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bzr branch, such as we display in the tree view at the top of the bzrk
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__copyright__ = "Copyright © 2005 Canonical Ltd."
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__author__ = "Scott James Remnant <scott@ubuntu.com>"
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from bzrlib.tsort import merge_sort
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def linegraph(repository, start, maxnum, broken_line_length=None):
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"""Produce a directed graph of a bzr repository.
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Returns a tuple of (line_graph, revid_index, columns_len) where
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* line_graph is a list of tuples of (revid,
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* revid_index is a dict of each revision with the key being the revid, and
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the value the row index, and
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* columns_len is the number of columns need to draw the line graph.
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Node is a tuple of (column, colour) with column being a zero-indexed
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column number of the graph that this revision represents and colour
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being a zero-indexed colour (which doesn't specify any actual colour
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in particular) to draw the node in.
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Lines is a list of tuples which represent lines you should draw away
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from the revision, if you also need to draw lines into the revision
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you should use the lines list from the previous iteration. Each
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typle in the list is in the form (start, end, colour) with start and
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end being zero-indexed column numbers and colour as in node.
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It's up to you how to actually draw the nodes and lines (straight,
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curved, kinked, etc.) and to pick the actual colours for each index.
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graph_parents = repository.get_revision_graph(start)
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for revid in graph_parents.iterkeys():
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graph_children[revid] = []
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if len(graph_parents)>0:
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merge_sorted_revisions = merge_sort(
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merge_sorted_revisions = ()
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# This will hold an item for each "branch". For a revisions, the revsion
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# number less the least significant digit is the branch_id, and used as the
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# key for the dict. Hence revision with the same revsion number less the
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# least significant digit are considered to be in the same branch line.
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# e.g.: for revisions 290.12.1 and 290.12.2, the branch_id would be 290.12,
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# and these two revisions will be in the same branch line. Each value is
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# a list of rev_indexes in the branch.
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for (rev_index, (sequence_number,
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end_of_merge)) in enumerate(merge_sorted_revisions):
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if maxnum and rev_index >= maxnum:
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revid_index[revid] = rev_index
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revno_index[revno_sequence] = rev_index
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branch_id = revno_sequence[0:-1]
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if branch_id not in branch_lines:
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branch_lines[branch_id] = branch_line
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branch_line = branch_lines[branch_id]
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branch_line.append(rev_index)
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parents = graph_parents[revid]
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for parent_revid in parents:
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graph_children[parent_revid].append(revid)
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linegraph.append([revid,
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branch_ids = branch_lines.keys()
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def branch_id_cmp(x, y):
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"""Compaire branch_id's first by the number of digits, then reversed
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return cmp(len_x, len_y)
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branch_ids.sort(branch_id_cmp)
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# This will hold a tuple of (child_index, parent_index, col_index) for each
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# line that needs to be drawn. If col_index is not none, then the line is
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# drawn along that column, else the the line can be drawn directly between
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# the child and parent because either the child and parent are in the same
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# branch line, or the child and parent are 1 row apart.
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empty_column = [False for i in range(len(graph_parents))]
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# This will hold a bit map for each cell. If the cell is true, then the
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# cell allready contains a node or line. This use when deciding what column
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# to place a branch line or line in, without it overlaping something else.
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columns = [list(empty_column)]
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for branch_id in branch_ids:
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branch_line = branch_lines[branch_id]
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# Find the col_index for the direct parent branch. This will be the
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# starting point when looking for a free column.
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if len(branch_id) > 1:
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parent_revno = branch_id[0:-1]
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if parent_revno in revno_index:
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parent_index = revno_index[parent_revno]
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parent_node = linegraph[parent_index][1]
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parent_col_index = parent_node[0]
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col_search_order = _branch_line_col_search_order(columns,
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color = reduce(lambda x, y: x+y, branch_id, 0)
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last_rev_index = None
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for rev_index in branch_line:
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if broken_line_length and \
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rev_index - last_rev_index > broken_line_length:
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line_range.append(last_rev_index+1)
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line_range.append(rev_index-1)
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line_range.extend(range(last_rev_index+1, rev_index))
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line_range.append(rev_index)
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last_rev_index = rev_index
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if broken_line_length and \
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parent_index - last_rev_index > broken_line_length:
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line_range.append(last_rev_index+1)
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line_range.extend(range(last_rev_index+1, parent_index))
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col_index = _find_free_column(columns,
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node = (col_index, color)
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for rev_index in branch_line:
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linegraph[rev_index][1] = node
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columns[col_index][rev_index] = True
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for rev_index in branch_line:
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end_of_merge) = merge_sorted_revisions[rev_index]
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linegraph[rev_index][4] = graph_children[revid]
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col_index = linegraph[rev_index][1][0]
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for parent_revid in graph_parents[revid]:
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if parent_revid in revid_index:
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parent_index = revid_index[parent_revid]
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parent_node = linegraph[parent_index][1]
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parent_col_index = parent_node[0]
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parent_col_index = None
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_line_col_search_order(columns,
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# If this line is really long, break it.
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if len(branch_id) > 0 and \
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broken_line_length and \
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parent_index - rev_index > broken_line_length:
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child_line_col_index = \
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_find_free_column(columns,
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_mark_column_as_used(columns,
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child_line_col_index,
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# Recall _line_col_search_order to reset it back to
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_line_col_search_order(columns,
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parent_col_line_index = \
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_find_free_column(columns,
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_mark_column_as_used(columns,
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parent_col_line_index,
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lines.append((rev_index,
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(child_line_col_index,
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parent_col_line_index)))
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line_col_index = col_index
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if parent_index - rev_index >1:
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line_range = range(rev_index + 1, parent_index)
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_find_free_column(columns,
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_mark_column_as_used(columns,
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lines.append((rev_index,
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for (child_index, parent_index, line_col_indexes) in lines:
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(child_col_index, child_color) = linegraph[child_index][1]
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(parent_col_index, parent_color) = linegraph[parent_index][1]
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if len(line_col_indexes) == 1:
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if parent_index - child_index == 1:
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linegraph[child_index][2].append(
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# line from the child's column to the lines column
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linegraph[child_index][2].append(
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# lines down the line's column
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for line_part_index in range(child_index+1, parent_index-1):
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linegraph[line_part_index][2].append(
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(line_col_indexes[0],
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# line from the line's column to the parent's column
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linegraph[parent_index-1][2].append(
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(line_col_indexes[0],
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# line from the child's column to the lines column
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linegraph[child_index][2].append(
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linegraph[child_index+1][2].append(
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(line_col_indexes[0],
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linegraph[parent_index-2][2].append(
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# line from the line's column to the parent's column
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linegraph[parent_index-1][2].append(
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(line_col_indexes[1],
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return (linegraph, revid_index, len(columns))
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def _branch_line_col_search_order(columns, parent_col_index):
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for col_index in range(parent_col_index, len(columns)):
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for col_index in range(parent_col_index-1, -1, -1):
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def _line_col_search_order(columns, parent_col_index, child_col_index):
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if parent_col_index is not None:
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max_index = max(parent_col_index, child_col_index)
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min_index = min(parent_col_index, child_col_index)
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for col_index in range(max_index, min_index -1, -1):
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max_index = child_col_index
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min_index = child_col_index
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yield child_col_index
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while max_index + i < len(columns) or \
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if max_index + i < len(columns):
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if min_index - i > -1:
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def _find_free_column(columns, empty_column, col_search_order, line_range):
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for col_index in col_search_order:
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column = columns[col_index]
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has_overlaping_line = False
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for row_index in line_range:
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if column[row_index]:
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has_overlaping_line = True
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if not has_overlaping_line:
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col_index = len(columns)
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column = list(empty_column)
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columns.append(column)
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def _mark_column_as_used(columns, col_index, line_range):
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column = columns[col_index]
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for row_index in line_range:
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column[row_index] = True
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def same_branch(a, b):
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"""Return whether we think revisions a and b are on the same branch."""
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if len(a.parent_ids) == 1:
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# Defacto same branch if only parent
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elif a.committer == b.committer:
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# Same committer so may as well be