/brz/remove-bazaar

# (C) 2005 Canonical

# This program is free software; you can redistribute it and/or modify

# it under the terms of the GNU General Public License as published by

# the Free Software Foundation; either version 2 of the License, or

# (at your option) any later version.

# This program is distributed in the hope that it will be useful,

# but WITHOUT ANY WARRANTY; without even the implied warranty of

# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the

# GNU General Public License for more details.

# You should have received a copy of the GNU General Public License

# along with this program; if not, write to the Free Software

# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA

# TODO: Some kind of command-line display of revision properties: 

# perhaps show them in log -v and allow them as options to the commit command.

import bzrlib.errors

import bzrlib.errors as errors

from bzrlib.graph import node_distances, select_farthest, all_descendants, Graph

from bzrlib.osutils import contains_whitespace

from bzrlib.progress import DummyProgress

from bzrlib.symbol_versioning import *

NULL_REVISION="null:"

class Revision(object):

    """Single revision on a branch.

    Revisions may know their revision_hash, but only once they've been

    written out.  This is not stored because you cannot write the hash

    into the file it describes.

    After bzr 0.0.5 revisions are allowed to have multiple parents.

    parent_ids

        List of parent revision_ids

    properties

        Dictionary of revision properties.  These are attached to the

        revision as extra metadata.  The name must be a single 

        word; the value can be an arbitrary string.

    """

    def __init__(self, revision_id, properties=None, **args):

        self.revision_id = revision_id

        self.properties = properties or {}

        self._check_properties()

        self.parent_ids = []

        self.parent_sha1s = []

        self.__dict__.update(args)

    def __repr__(self):

        return "<Revision id %s>" % self.revision_id

    def __eq__(self, other):

        if not isinstance(other, Revision):

            return False

        # FIXME: rbc 20050930 parent_ids are not being compared

        return (

                self.inventory_sha1 == other.inventory_sha1

                and self.revision_id == other.revision_id

                and self.timestamp == other.timestamp

                and self.message == other.message

                and self.timezone == other.timezone

                and self.committer == other.committer

                and self.properties == other.properties)

    def __ne__(self, other):

        return not self.__eq__(other)

    def _check_properties(self):

        """Verify that all revision properties are OK.

        """

        for name, value in self.properties.iteritems():

            if not isinstance(name, basestring) or contains_whitespace(name):

                raise ValueError("invalid property name %r" % name)

            if not isinstance(value, basestring):

                raise ValueError("invalid property value %r for %r" % 

                                 (name, value))

    def get_history(self, repository):

        """Return the canonical line-of-history for this revision.

        If ghosts are present this may differ in result from a ghost-free

        repository.

        """

        current_revision = self

        reversed_result = []

        while current_revision is not None:

            reversed_result.append(current_revision.revision_id)

            if not len (current_revision.parent_ids):

                reversed_result.append(None)

                current_revision = None

            else:

                next_revision_id = current_revision.parent_ids[0]

                current_revision = repository.get_revision(next_revision_id)

        reversed_result.reverse()

        return reversed_result

    def get_summary(self):

        """Get the first line of the log message for this revision.

        """

        return self.message.split('\n', 1)[0]

def is_ancestor(revision_id, candidate_id, branch):

    """Return true if candidate_id is an ancestor of revision_id.

    A false negative will be returned if any intermediate descendent of

    candidate_id is not present in any of the revision_sources.

    revisions_source is an object supporting a get_revision operation that

    behaves like Branch's.

    """

    return candidate_id in branch.repository.get_ancestry(revision_id)

def iter_ancestors(revision_id, revision_source, only_present=False):

    ancestors = (revision_id,)

    distance = 0

    while len(ancestors) > 0:

        new_ancestors = []

        for ancestor in ancestors:

            if not only_present:

                yield ancestor, distance

            try:

                revision = revision_source.get_revision(ancestor)

            except bzrlib.errors.NoSuchRevision, e:

                if e.revision == revision_id:

                    raise 

                else:

                    continue

            if only_present:

                yield ancestor, distance

            new_ancestors.extend(revision.parent_ids)

        ancestors = new_ancestors

        distance += 1

def find_present_ancestors(revision_id, revision_source):

    """Return the ancestors of a revision present in a branch.

    It's possible that a branch won't have the complete ancestry of

    one of its revisions.  

    """

    found_ancestors = {}

    anc_iter = enumerate(iter_ancestors(revision_id, revision_source,

                         only_present=True))

    for anc_order, (anc_id, anc_distance) in anc_iter:

        if not found_ancestors.has_key(anc_id):

            found_ancestors[anc_id] = (anc_order, anc_distance)

    return found_ancestors

def __get_closest(intersection):

    intersection.sort()

    matches = [] 

    for entry in intersection:

        if entry[0] == intersection[0][0]:

            matches.append(entry[2])

    return matches

def revision_graph(revision, revision_source):

    """Produce a graph of the ancestry of the specified revision.

    :return: root, ancestors map, descendants map

    """

    revision_source.lock_read()

    try:

        return _revision_graph(revision, revision_source)

    finally:

        revision_source.unlock()

def _revision_graph(revision, revision_source):

    """See revision_graph."""

    from bzrlib.tsort import topo_sort

    graph = revision_source.get_revision_graph(revision)

    # mark all no-parent revisions as being NULL_REVISION parentage.

    for node, parents in graph.items():

        if len(parents) == 0:

            graph[node] = [NULL_REVISION]

    # add NULL_REVISION to the graph

    graph[NULL_REVISION] = []

    # pick a root. If there are multiple roots

    # this could pick a random one.

    topo_order = topo_sort(graph.items())

    root = topo_order[0]

    ancestors = {}

    descendants = {}

    # map the descendants of the graph.

    # and setup our set based return graph.

    for node in graph.keys():

        descendants[node] = {}

    for node, parents in graph.items():

        for parent in parents:

            descendants[parent][node] = 1

        ancestors[node] = set(parents)

    assert root not in descendants[root]

    assert root not in ancestors[root]

    return root, ancestors, descendants

def combined_graph(revision_a, revision_b, revision_source):

    """Produce a combined ancestry graph.

    Return graph root, ancestors map, descendants map, set of common nodes"""

    root, ancestors, descendants = revision_graph(

        revision_a, revision_source)

    root_b, ancestors_b, descendants_b = revision_graph(

        revision_b, revision_source)

    if root != root_b:

        raise bzrlib.errors.NoCommonRoot(revision_a, revision_b)

    common = set()

    for node, node_anc in ancestors_b.iteritems():

        if node in ancestors:

            common.add(node)

        else:

            ancestors[node] = set()

        ancestors[node].update(node_anc)

    for node, node_dec in descendants_b.iteritems():

        if node not in descendants:

            descendants[node] = {}

        descendants[node].update(node_dec)

    return root, ancestors, descendants, common

def common_ancestor(revision_a, revision_b, revision_source, 

                    pb=DummyProgress()):

    if None in (revision_a, revision_b):

        return None

    # trivial optimisation

    if revision_a == revision_b:

        return revision_a

    try:

        try:

            pb.update('Picking ancestor', 1, 3)

            graph = revision_source.get_revision_graph_with_ghosts(

                [revision_a, revision_b])

            # convert to a NULL_REVISION based graph.

            ancestors = graph.get_ancestors()

            descendants = graph.get_descendants()

            common = set(graph.get_ancestry(revision_a)).intersection(

                     set(graph.get_ancestry(revision_b)))

            descendants[NULL_REVISION] = {}

            ancestors[NULL_REVISION] = []

            for root in graph.roots:

                descendants[NULL_REVISION][root] = 1

                ancestors[root].append(NULL_REVISION)

            for ghost in graph.ghosts:

                # ghosts act as roots for the purpose of finding 

                # the longest paths from the root: any ghost *might*

                # be directly attached to the root, so we treat them

                # as being such.

                # ghost now descends from NULL

                descendants[NULL_REVISION][ghost] = 1

                # that is it has an ancestor of NULL

                ancestors[ghost] = [NULL_REVISION]

                # ghost is common if any of ghosts descendants are common:

                for ghost_descendant in descendants[ghost]:

                    if ghost_descendant in common:

                        common.add(ghost)

            root = NULL_REVISION

            common.add(NULL_REVISION)

        except bzrlib.errors.NoCommonRoot:

            raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)

        pb.update('Picking ancestor', 2, 3)

        distances = node_distances (descendants, ancestors, root)

        pb.update('Picking ancestor', 3, 2)

        farthest = select_farthest(distances, common)

        if farthest is None or farthest == NULL_REVISION:

            raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)

    finally:

        pb.clear()

    return farthest

class MultipleRevisionSources(object):

    """Proxy that looks in multiple branches for revisions."""

    def __init__(self, *args):

        object.__init__(self)

        assert len(args) != 0

        self._revision_sources = args

    def revision_parents(self, revision_id):

        for source in self._revision_sources:

            try:

                return source.revision_parents(revision_id)

            except (errors.WeaveRevisionNotPresent, errors.NoSuchRevision), e:

                pass

        raise e

    def get_revision(self, revision_id):

        for source in self._revision_sources:

            try:

                return source.get_revision(revision_id)

            except bzrlib.errors.NoSuchRevision, e:

                pass

        raise e

    def get_revision_graph(self, revision_id):

        # we could probe incrementally until the pending

        # ghosts list stop growing, but its cheaper for now

        # to just ask for the complete graph for each repository.

        graphs = []

        for source in self._revision_sources:

            ghost_graph = source.get_revision_graph_with_ghosts()

            graphs.append(ghost_graph)

        absent = 0

        for graph in graphs:

            if not revision_id in graph.get_ancestors():

                absent += 1

        if absent == len(graphs):

            raise errors.NoSuchRevision(self._revision_sources[0], revision_id)

        # combine the graphs

        result = {}

        pending = set([revision_id])

        def find_parents(node_id):

            """find the parents for node_id."""

            for graph in graphs:

                ancestors = graph.get_ancestors()

                try:

                    return ancestors[node_id]

                except KeyError:

                    pass

            raise errors.NoSuchRevision(self._revision_sources[0], node_id)

        while len(pending):

            # all the graphs should have identical parent lists

            node_id = pending.pop()

            try:

                result[node_id] = find_parents(node_id)

                for parent_node in result[node_id]:

                    if not parent_node in result:

                        pending.add(parent_node)

            except errors.NoSuchRevision:

                # ghost, ignore it.

                pass

        return result

    def get_revision_graph_with_ghosts(self, revision_ids):

        # query all the sources for their entire graphs 

        # and then build a combined graph for just

        # revision_ids.

        graphs = []

        for source in self._revision_sources:

            ghost_graph = source.get_revision_graph_with_ghosts()

            graphs.append(ghost_graph.get_ancestors())

        for revision_id in revision_ids:

            absent = 0

            for graph in graphs:

                    if not revision_id in graph:

                        absent += 1

            if absent == len(graphs):

                raise errors.NoSuchRevision(self._revision_sources[0],

                                            revision_id)

        # combine the graphs

        result = Graph()

        pending = set(revision_ids)

        done = set()

        def find_parents(node_id):

            """find the parents for node_id."""

            for graph in graphs:

                try:

                    return graph[node_id]

                except KeyError:

                    pass

            raise errors.NoSuchRevision(self._revision_sources[0], node_id)

        while len(pending):

            # all the graphs should have identical parent lists

            node_id = pending.pop()

            try:

                parents = find_parents(node_id)

                for parent_node in parents:

                    # queued or done? 

                    if (parent_node not in pending and

                        parent_node not in done):

                        # no, queue

                        pending.add(parent_node)

                result.add_node(node_id, parents)

                done.add(node_id)

            except errors.NoSuchRevision:

                # ghost

                result.add_ghost(node_id)

                continue

        return result

    def lock_read(self):

        for source in self._revision_sources:

            source.lock_read()

    def unlock(self):

        for source in self._revision_sources:

            source.unlock()

@deprecated_function(zero_eight)

def get_intervening_revisions(ancestor_id, rev_id, rev_source,

                              revision_history=None):

    """Find the longest line of descent from maybe_ancestor to revision.

    Revision history is followed where possible.

    If ancestor_id == rev_id, list will be empty.

    Otherwise, rev_id will be the last entry.  ancestor_id will never appear.

    If ancestor_id is not an ancestor, NotAncestor will be thrown

    """

    root, ancestors, descendants = revision_graph(rev_id, rev_source)

    if len(descendants) == 0:

        raise NoSuchRevision(rev_source, rev_id)

    if ancestor_id not in descendants:

        rev_source.get_revision(ancestor_id)

        raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)

    root_descendants = all_descendants(descendants, ancestor_id)

    root_descendants.add(ancestor_id)

    if rev_id not in root_descendants:

        raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)

    distances = node_distances(descendants, ancestors, ancestor_id,

                               root_descendants=root_descendants)

    def best_ancestor(rev_id):

        best = None

        for anc_id in ancestors[rev_id]:

            try:

                distance = distances[anc_id]

            except KeyError:

                continue

            if revision_history is not None and anc_id in revision_history:

                return anc_id

            elif best is None or distance > best[1]:

                best = (anc_id, distance)

        return best[0]

    next = rev_id

    path = []

    while next != ancestor_id:

        path.append(next)

        next = best_ancestor(next)

    path.reverse()

    return path