/brz/remove-bazaar

# Copyright (C) 2007 Canonical Ltd

#

# This program is free software; you can redistribute it and/or modify

# it under the terms of the GNU General Public License as published by

# the Free Software Foundation; either version 2 of the License, or

# (at your option) any later version.

#

# This program is distributed in the hope that it will be useful,

# but WITHOUT ANY WARRANTY; without even the implied warranty of

# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the

# GNU General Public License for more details.

#

# You should have received a copy of the GNU General Public License

# along with this program; if not, write to the Free Software

# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA

from bzrlib import (

    errors,

    graph as _mod_graph,

    )

from bzrlib.revision import NULL_REVISION

from bzrlib.tests import TestCaseWithMemoryTransport

# Ancestry 1:

#

#  NULL_REVISION

#       |

#     rev1

#      /\

#  rev2a rev2b

#     |    |

#   rev3  /

#     |  /

#   rev4

ancestry_1 = {'rev1': [NULL_REVISION], 'rev2a': ['rev1'], 'rev2b': ['rev1'],

              'rev3': ['rev2a'], 'rev4': ['rev3', 'rev2b']}

# Ancestry 2:

#

#  NULL_REVISION

#    /    \

# rev1a  rev1b

#   |

# rev2a

#   |

# rev3a

#   |

# rev4a

ancestry_2 = {'rev1a': [NULL_REVISION], 'rev2a': ['rev1a'],

              'rev1b': [NULL_REVISION], 'rev3a': ['rev2a'], 'rev4a': ['rev3a']}

# Criss cross ancestry

#

#     NULL_REVISION

#         |

#        rev1

#        /  \

#    rev2a  rev2b

#       |\  /|

#       |  X |

#       |/  \|

#    rev3a  rev3b

criss_cross = {'rev1': [NULL_REVISION], 'rev2a': ['rev1'], 'rev2b': ['rev1'],

               'rev3a': ['rev2a', 'rev2b'], 'rev3b': ['rev2b', 'rev2a']}

# Criss-cross 2

#

#  NULL_REVISION

#    /   \

# rev1a  rev1b

#   |\   /|

#   | \ / |

#   |  X  |

#   | / \ |

#   |/   \|

# rev2a  rev2b

criss_cross2 = {'rev1a': [NULL_REVISION], 'rev1b': [NULL_REVISION],

                'rev2a': ['rev1a', 'rev1b'], 'rev2b': ['rev1b', 'rev1a']}

# Mainline:

#

#  NULL_REVISION

#       |

#      rev1

#      /  \

#      | rev2b

#      |  /

#     rev2a

mainline = {'rev1': [NULL_REVISION], 'rev2a': ['rev1', 'rev2b'],

            'rev2b': ['rev1']}

# feature branch:

#

#  NULL_REVISION

#       |

#      rev1

#       |

#     rev2b

#       |

#     rev3b

feature_branch = {'rev1': [NULL_REVISION],

                  'rev2b': ['rev1'], 'rev3b': ['rev2b']}

# History shortcut

#  NULL_REVISION

#       |

#     rev1------

#     /  \      \

#  rev2a rev2b rev2c

#    |  /   \   /

#  rev3a    reveb

history_shortcut = {'rev1': [NULL_REVISION], 'rev2a': ['rev1'],

                    'rev2b': ['rev1'], 'rev2c': ['rev1'],

                    'rev3a': ['rev2a', 'rev2b'], 'rev3b': ['rev2b', 'rev2c']}

#  NULL_REVISION

#       |

#       f

#       |

#       e

#      / \

#     b   d

#     | \ |

#     a   c

boundary = {'a': ['b'], 'c': ['b', 'd'], 'b':['e'], 'd':['e'], 'e': ['f'],

            'f':[NULL_REVISION]}

class InstrumentedParentsProvider(object):

    def __init__(self, parents_provider):

        self.calls = []

        self._real_parents_provider = parents_provider

    def get_parents(self, nodes):

        self.calls.extend(nodes)

        return self._real_parents_provider.get_parents(nodes)

class TestGraph(TestCaseWithMemoryTransport):

    def make_graph(self, ancestors):

        tree = self.prepare_memory_tree('.')

        self.build_ancestry(tree, ancestors)

        tree.unlock()

        return tree.branch.repository.get_graph()

    def prepare_memory_tree(self, location):

        tree = self.make_branch_and_memory_tree(location)

        tree.lock_write()

        tree.add('.')

        return tree

    def build_ancestry(self, tree, ancestors):

        """Create an ancestry as specified by a graph dict

        :param tree: A tree to use

        :param ancestors: a dict of {node: [node_parent, ...]}

        """

        pending = [NULL_REVISION]

        descendants = {}

        for descendant, parents in ancestors.iteritems():

            for parent in parents:

                descendants.setdefault(parent, []).append(descendant)

        while len(pending) > 0:

            cur_node = pending.pop()

            for descendant in descendants.get(cur_node, []):

                if tree.branch.repository.has_revision(descendant):

                    continue

                parents = [p for p in ancestors[descendant] if p is not

                           NULL_REVISION]

                if len([p for p in parents if not

                    tree.branch.repository.has_revision(p)]) > 0:

                    continue

                tree.set_parent_ids(parents)

                if len(parents) > 0:

                    left_parent = parents[0]

                else:

                    left_parent = NULL_REVISION

                tree.branch.set_last_revision_info(

                    len(tree.branch._lefthand_history(left_parent)),

                    left_parent)

                tree.commit(descendant, rev_id=descendant)

                pending.append(descendant)

    def test_lca(self):

        """Test finding least common ancestor.

        ancestry_1 should always have a single common ancestor

        """

        graph = self.make_graph(ancestry_1)

        self.assertRaises(errors.InvalidRevisionId, graph.find_lca, None)

        self.assertEqual(set([NULL_REVISION]),

                         graph.find_lca(NULL_REVISION, NULL_REVISION))

        self.assertEqual(set([NULL_REVISION]),

                         graph.find_lca(NULL_REVISION, 'rev1'))

        self.assertEqual(set(['rev1']), graph.find_lca('rev1', 'rev1'))

        self.assertEqual(set(['rev1']), graph.find_lca('rev2a', 'rev2b'))

    def test_no_unique_lca(self):

        """Test error when one revision is not in the graph"""

        graph = self.make_graph(ancestry_1)

        self.assertRaises(errors.NoCommonAncestor, graph.find_unique_lca,

                          'rev1', '1rev')

    def test_lca_criss_cross(self):

        """Test least-common-ancestor after a criss-cross merge."""

        graph = self.make_graph(criss_cross)

        self.assertEqual(set(['rev2a', 'rev2b']),

                         graph.find_lca('rev3a', 'rev3b'))

        self.assertEqual(set(['rev2b']),

                         graph.find_lca('rev3a', 'rev3b', 'rev2b'))

    def test_lca_shortcut(self):

        """Test least-common ancestor on this history shortcut"""

        graph = self.make_graph(history_shortcut)

        self.assertEqual(set(['rev2b']), graph.find_lca('rev3a', 'rev3b'))

    def test_recursive_unique_lca(self):

        """Test finding a unique least common ancestor.

        ancestry_1 should always have a single common ancestor

        """

        graph = self.make_graph(ancestry_1)

        self.assertEqual(NULL_REVISION,

                         graph.find_unique_lca(NULL_REVISION, NULL_REVISION))

        self.assertEqual(NULL_REVISION,

                         graph.find_unique_lca(NULL_REVISION, 'rev1'))

        self.assertEqual('rev1', graph.find_unique_lca('rev1', 'rev1'))

        self.assertEqual('rev1', graph.find_unique_lca('rev2a', 'rev2b'))

    def test_unique_lca_criss_cross(self):

        """Ensure we don't pick non-unique lcas in a criss-cross"""

        graph = self.make_graph(criss_cross)

        self.assertEqual('rev1', graph.find_unique_lca('rev3a', 'rev3b'))

    def test_unique_lca_null_revision(self):

        """Ensure we pick NULL_REVISION when necessary"""

        graph = self.make_graph(criss_cross2)

        self.assertEqual('rev1b', graph.find_unique_lca('rev2a', 'rev1b'))

        self.assertEqual(NULL_REVISION,

                         graph.find_unique_lca('rev2a', 'rev2b'))

    def test_unique_lca_null_revision2(self):

        """Ensure we pick NULL_REVISION when necessary"""

        graph = self.make_graph(ancestry_2)

        self.assertEqual(NULL_REVISION,

                         graph.find_unique_lca('rev4a', 'rev1b'))

    def test_common_ancestor_two_repos(self):

        """Ensure we do unique_lca using data from two repos"""

        mainline_tree = self.prepare_memory_tree('mainline')

        self.build_ancestry(mainline_tree, mainline)

        mainline_tree.unlock()

        # This is cheating, because the revisions in the graph are actually

        # different revisions, despite having the same revision-id.

        feature_tree = self.prepare_memory_tree('feature')

        self.build_ancestry(feature_tree, feature_branch)

        feature_tree.unlock()

        graph = mainline_tree.branch.repository.get_graph(

            feature_tree.branch.repository)

        self.assertEqual('rev2b', graph.find_unique_lca('rev2a', 'rev3b'))

    def test_graph_difference(self):

        graph = self.make_graph(ancestry_1)

        self.assertEqual((set(), set()), graph.find_difference('rev1', 'rev1'))

        self.assertEqual((set(), set(['rev1'])),

                         graph.find_difference(NULL_REVISION, 'rev1'))

        self.assertEqual((set(['rev1']), set()),

                         graph.find_difference('rev1', NULL_REVISION))

        self.assertEqual((set(['rev2a', 'rev3']), set(['rev2b'])),

                         graph.find_difference('rev3', 'rev2b'))

        self.assertEqual((set(['rev4', 'rev3', 'rev2a']), set()),

                         graph.find_difference('rev4', 'rev2b'))

    def test_graph_difference_criss_cross(self):

        graph = self.make_graph(criss_cross)

        self.assertEqual((set(['rev3a']), set(['rev3b'])),

                         graph.find_difference('rev3a', 'rev3b'))

        self.assertEqual((set([]), set(['rev3b', 'rev2b'])),

                         graph.find_difference('rev2a', 'rev3b'))

    def test_stacked_parents_provider(self):

        class ParentsProvider(object):

            def __init__(self, ancestry):

                self.ancestry = ancestry

            def get_parents(self, revisions):

                return [self.ancestry.get(r, None) for r in revisions]

        parents1 = ParentsProvider({'rev2': ['rev3']})

        parents2 = ParentsProvider({'rev1': ['rev4']})

        stacked = _mod_graph._StackedParentsProvider([parents1, parents2])

        self.assertEqual([['rev4',], ['rev3']],

                         stacked.get_parents(['rev1', 'rev2']))

        self.assertEqual([['rev3',], ['rev4']],

                         stacked.get_parents(['rev2', 'rev1']))

        self.assertEqual([['rev3',], ['rev3']],

                         stacked.get_parents(['rev2', 'rev2']))

        self.assertEqual([['rev4',], ['rev4']],

                         stacked.get_parents(['rev1', 'rev1']))

    def test_iter_topo_order(self):

        graph = self.make_graph(ancestry_1)

        args = ['rev2a', 'rev3', 'rev1']

        topo_args = list(graph.iter_topo_order(args))

        self.assertEqual(set(args), set(topo_args))

        self.assertTrue(topo_args.index('rev2a') > topo_args.index('rev1'))

        self.assertTrue(topo_args.index('rev2a') < topo_args.index('rev3'))

    def test_is_ancestor(self):

        graph = self.make_graph(ancestry_1)

        self.assertEqual(True, graph.is_ancestor('null:', 'null:'))

        self.assertEqual(True, graph.is_ancestor('null:', 'rev1'))

        self.assertEqual(False, graph.is_ancestor('rev1', 'null:'))

        self.assertEqual(True, graph.is_ancestor('null:', 'rev4'))

        self.assertEqual(False, graph.is_ancestor('rev4', 'null:'))

        self.assertEqual(False, graph.is_ancestor('rev4', 'rev2b'))

        self.assertEqual(True, graph.is_ancestor('rev2b', 'rev4'))

        self.assertEqual(False, graph.is_ancestor('rev2b', 'rev3'))

        self.assertEqual(False, graph.is_ancestor('rev3', 'rev2b'))

        instrumented_provider = InstrumentedParentsProvider(graph)

        instrumented_graph = _mod_graph.Graph(instrumented_provider)

        instrumented_graph.is_ancestor('rev2a', 'rev2b')

        self.assertTrue('null:' not in instrumented_provider.calls)

    def test_is_ancestor_boundary(self):

        """Ensure that we avoid searching the whole graph.

        This requires searching through b as a common ancestor, so we

        can identify that e is common.

        """

        graph = self.make_graph(boundary)

        instrumented_provider = InstrumentedParentsProvider(graph)

        graph = _mod_graph.Graph(instrumented_provider)

        self.assertFalse(graph.is_ancestor('a', 'c'))

        self.assertTrue('null:' not in instrumented_provider.calls)