/brz/remove-bazaar

# Copyright (C) 2005, 2006 Canonical Ltd

#

# This program is free software; you can redistribute it and/or modify

# it under the terms of the GNU General Public License as published by

# the Free Software Foundation; either version 2 of the License, or

# (at your option) any later version.

#

# This program is distributed in the hope that it will be useful,

# but WITHOUT ANY WARRANTY; without even the implied warranty of

# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the

# GNU General Public License for more details.

#

# You should have received a copy of the GNU General Public License

# along with this program; if not, write to the Free Software

# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA

"""Display what revisions are missing in 'other' from 'this' and vice versa."""

from . import (

    errors,

    log,

    )

def iter_log_revisions(revisions, revision_source, verbose, rev_tag_dict=None):

    if rev_tag_dict is None:

        rev_tag_dict = {}

    for revno, rev_id, merge_depth in revisions:

        rev = revision_source.get_revision(rev_id)

        if verbose:

            delta = revision_source.get_revision_delta(rev_id)

        else:

            delta = None

        yield log.LogRevision(rev, revno, merge_depth, delta=delta,

                              tags=rev_tag_dict.get(rev_id))

def find_unmerged(local_branch, remote_branch, restrict='all',

                  include_merged=None, backward=False,

                  local_revid_range=None, remote_revid_range=None):

    """Find revisions from each side that have not been merged.

    :param local_branch: Compare the history of local_branch

    :param remote_branch: versus the history of remote_branch, and determine

        mainline revisions which have not been merged.

    :param restrict: ('all', 'local', 'remote') If 'all', we will return the

        unique revisions from both sides. If 'local', we will return None

        for the remote revisions, similarly if 'remote' we will return None for

        the local revisions.

    :param include_merged: Show mainline revisions only if False,

        all revisions otherwise.

    :param backward: Show oldest versions first when True, newest versions

        first when False.

    :param local_revid_range: Revision-id range for filtering local_branch

        revisions (lower bound, upper bound)

    :param remote_revid_range: Revision-id range for filtering remote_branch

        revisions (lower bound, upper bound)

    :return: A list of [(revno, revision_id)] for the mainline revisions on

        each side.

    """

    if include_merged is None:

        include_merged = False

    with local_branch.lock_read(), remote_branch.lock_read():

        return _find_unmerged(

            local_branch, remote_branch, restrict=restrict,

            include_merged=include_merged, backward=backward,

            local_revid_range=local_revid_range,

            remote_revid_range=remote_revid_range)

def _enumerate_mainline(ancestry, graph, tip_revno, tip, backward=True):

    """Enumerate the mainline revisions for these revisions.

    :param ancestry: A set of revisions that we care about

    :param graph: A Graph which lets us find the parents for a revision

    :param tip_revno: The revision number for the tip revision

    :param tip: The tip of mainline

    :param backward: Show oldest versions first when True, newest versions

        first when False.

    :return: [(revno, revision_id, 0)] for all revisions in ancestry that

        are left-hand parents from tip, or None if ancestry is None.

    """

    if ancestry is None:

        return None

    if not ancestry:  # Empty ancestry, no need to do any work

        return []

    # Optionally, we could make 1 call to graph.get_parent_map with all

    # ancestors. However that will often check many more parents than we

    # actually need, and the Graph is likely to already have the parents cached

    # anyway.

    mainline = []

    cur = tip

    cur_revno = tip_revno

    while cur in ancestry:

        parent_map = graph.get_parent_map([cur])

        parents = parent_map.get(cur)

        if not parents:

            break  # Ghost, we are done

        mainline.append(

            (str(cur_revno) if cur_revno is not None else None, cur, 0))

        cur = parents[0]

        if cur_revno is not None:

            cur_revno -= 1

    if not backward:

        mainline.reverse()

    return mainline

def _enumerate_with_merges(branch, ancestry, graph, tip_revno, tip,

                           backward=True):

    """Enumerate the revisions for the ancestry.

    :param branch: The branch we care about

    :param ancestry: A set of revisions that we care about

    :param graph: A Graph which lets us find the parents for a revision

    :param tip_revno: The revision number for the tip revision

    :param tip: The tip of the ancsetry

    :param backward: Show oldest versions first when True, newest versions

        first when False.

    :return: [(revno, revision_id)] for all revisions in ancestry that

        are parents from tip, or None if ancestry is None.

    """

    if ancestry is None:

        return None

    if not ancestry:  # Empty ancestry, no need to do any work

        return []

    merge_sorted_revisions = branch.iter_merge_sorted_revisions()

    # Now that we got the correct revnos, keep only the relevant

    # revisions.

    merge_sorted_revisions = [

        # log.reverse_by_depth expects seq_num to be present, but it is

        # stripped by iter_merge_sorted_revisions()

        (0, revid, n, d, e) for revid, n, d, e in merge_sorted_revisions

        if revid in ancestry]

    if not backward:

        merge_sorted_revisions = log.reverse_by_depth(merge_sorted_revisions)

    revline = []

    for seq, rev_id, merge_depth, revno, end_of_merge in merge_sorted_revisions:

        revline.append(('.'.join(map(str, revno)), rev_id, merge_depth))

    return revline

def _filter_revs(graph, revs, revid_range):

    if revid_range is None or revs is None:

        return revs

    return [rev for rev in revs

            if graph.is_between(rev[1], revid_range[0], revid_range[1])]

def _find_unmerged(local_branch, remote_branch, restrict,

                   include_merged, backward,

                   local_revid_range=None, remote_revid_range=None):

    """See find_unmerged.

    The branches should already be locked before entering.

    """

    try:

        local_revno, local_revision_id = local_branch.last_revision_info()

    except (errors.UnsupportedOperation, errors.GhostRevisionsHaveNoRevno):

        local_revno = None

        local_revision_id = local_branch.last_revision()

    try:

        remote_revno, remote_revision_id = remote_branch.last_revision_info()

    except (errors.UnsupportedOperation, errors.GhostRevisionsHaveNoRevno):

        remote_revision_id = remote_branch.last_revision()

        remote_revno = None

    if local_revision_id == remote_revision_id:

        # A simple shortcut when the tips are at the same point

        return [], []

    graph = local_branch.repository.get_graph(remote_branch.repository)

    if restrict == 'remote':

        local_extra = None

        remote_extra = graph.find_unique_ancestors(remote_revision_id,

                                                   [local_revision_id])

    elif restrict == 'local':

        remote_extra = None

        local_extra = graph.find_unique_ancestors(local_revision_id,

                                                  [remote_revision_id])

    else:

        if restrict != 'all':

            raise ValueError('param restrict not one of "all", "local",'

                             ' "remote": %r' % (restrict,))

        local_extra, remote_extra = graph.find_difference(local_revision_id,

                                                          remote_revision_id)

    if include_merged:

        locals = _enumerate_with_merges(local_branch, local_extra,

                                        graph, local_revno,

                                        local_revision_id, backward)

        remotes = _enumerate_with_merges(remote_branch, remote_extra,

                                         graph, remote_revno,

                                         remote_revision_id, backward)

    else:

        # Now that we have unique ancestors, compute just the mainline, and

        # generate revnos for them.

        locals = _enumerate_mainline(local_extra, graph, local_revno,

                                     local_revision_id, backward)

        remotes = _enumerate_mainline(remote_extra, graph, remote_revno,

                                      remote_revision_id, backward)

    return _filter_revs(graph, locals, local_revid_range), _filter_revs(

        graph, remotes, remote_revid_range)

def sorted_revisions(revisions, history_map):

    revisions = sorted([(history_map[r], r) for r in revisions])

    return revisions