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# Copyright (C) 2007 Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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from bzrlib.deprecated_graph import (node_distances, select_farthest)
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from bzrlib.revision import NULL_REVISION
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# DIAGRAM of terminology
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# In this diagram, relative to G and H:
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# A, B, C, D, E are common ancestors.
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# C, D and E are border ancestors, because each has a non-common descendant.
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# D and E are least common ancestors because none of their descendants are
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# C is not a least common ancestor because its descendant, E, is a common
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# The find_unique_lca algorithm will pick A in two steps:
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# 1. find_lca('G', 'H') => ['D', 'E']
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# 2. Since len(['D', 'E']) > 1, find_lca('D', 'E') => ['A']
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class _StackedParentsProvider(object):
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def __init__(self, parent_providers):
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self._parent_providers = parent_providers
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return "_StackedParentsProvider(%r)" % self._parent_providers
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def get_parents(self, revision_ids):
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"""Find revision ids of the parents of a list of revisions
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A list is returned of the same length as the input. Each entry
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is a list of parent ids for the corresponding input revision.
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[NULL_REVISION] is used as the parent of the first user-committed
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revision. Its parent list is empty.
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If the revision is not present (i.e. a ghost), None is used in place
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of the list of parents.
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for parents_provider in self._parent_providers:
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pending_revisions = [r for r in revision_ids if r not in found]
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parent_list = parents_provider.get_parents(pending_revisions)
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new_found = dict((k, v) for k, v in zip(pending_revisions,
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parent_list) if v is not None)
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found.update(new_found)
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if len(found) == len(revision_ids):
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return [found.get(r, None) for r in revision_ids]
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"""Provide incremental access to revision graphs.
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This is the generic implementation; it is intended to be subclassed to
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specialize it for other repository types.
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def __init__(self, parents_provider):
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"""Construct a Graph that uses several graphs as its input
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This should not normally be invoked directly, because there may be
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specialized implementations for particular repository types. See
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Repository.get_graph()
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:param parents_func: an object providing a get_parents call
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conforming to the behavior of StackedParentsProvider.get_parents
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self.get_parents = parents_provider.get_parents
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self._parents_provider = parents_provider
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return 'Graph(%r)' % self._parents_provider
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def find_lca(self, *revisions):
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"""Determine the lowest common ancestors of the provided revisions
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A lowest common ancestor is a common ancestor none of whose
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descendants are common ancestors. In graphs, unlike trees, there may
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be multiple lowest common ancestors.
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This algorithm has two phases. Phase 1 identifies border ancestors,
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and phase 2 filters border ancestors to determine lowest common
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In phase 1, border ancestors are identified, using a breadth-first
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search starting at the bottom of the graph. Searches are stopped
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whenever a node or one of its descendants is determined to be common
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In phase 2, the border ancestors are filtered to find the least
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common ancestors. This is done by searching the ancestries of each
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Phase 2 is perfomed on the principle that a border ancestor that is
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not an ancestor of any other border ancestor is a least common
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Searches are stopped when they find a node that is determined to be a
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common ancestor of all border ancestors, because this shows that it
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cannot be a descendant of any border ancestor.
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The scaling of this operation should be proportional to
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1. The number of uncommon ancestors
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2. The number of border ancestors
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3. The length of the shortest path between a border ancestor and an
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ancestor of all border ancestors.
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border_common, common, sides = self._find_border_ancestors(revisions)
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# We may have common ancestors that can be reached from each other.
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# - ask for the heads of them to filter it down to only ones that
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# cannot be reached from each other - phase 2.
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return self.heads(border_common)
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def find_difference(self, left_revision, right_revision):
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"""Determine the graph difference between two revisions"""
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border, common, (left, right) = self._find_border_ancestors(
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[left_revision, right_revision])
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return (left.difference(right).difference(common),
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right.difference(left).difference(common))
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def _make_breadth_first_searcher(self, revisions):
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return _BreadthFirstSearcher(revisions, self)
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def _find_border_ancestors(self, revisions):
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"""Find common ancestors with at least one uncommon descendant.
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Border ancestors are identified using a breadth-first
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search starting at the bottom of the graph. Searches are stopped
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whenever a node or one of its descendants is determined to be common.
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This will scale with the number of uncommon ancestors.
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As well as the border ancestors, a set of seen common ancestors and a
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list of sets of seen ancestors for each input revision is returned.
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This allows calculation of graph difference from the results of this
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if None in revisions:
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raise errors.InvalidRevisionId(None, self)
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common_searcher = self._make_breadth_first_searcher([])
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common_ancestors = set()
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searchers = [self._make_breadth_first_searcher([r])
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active_searchers = searchers[:]
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border_ancestors = set()
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def update_common(searcher, revisions):
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w_seen_ancestors = searcher.find_seen_ancestors(
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stopped = searcher.stop_searching_any(w_seen_ancestors)
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common_ancestors.update(w_seen_ancestors)
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common_searcher.start_searching(stopped)
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if len(active_searchers) == 0:
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return border_ancestors, common_ancestors, [s.seen for s in
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new_common = common_searcher.next()
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common_ancestors.update(new_common)
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except StopIteration:
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for searcher in active_searchers:
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for revision in new_common.intersection(searcher.seen):
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update_common(searcher, revision)
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new_active_searchers = []
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for searcher in active_searchers:
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newly_seen.update(searcher.next())
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except StopIteration:
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new_active_searchers.append(searcher)
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active_searchers = new_active_searchers
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for revision in newly_seen:
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if revision in common_ancestors:
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for searcher in searchers:
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update_common(searcher, revision)
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for searcher in searchers:
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if revision not in searcher.seen:
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border_ancestors.add(revision)
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for searcher in searchers:
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update_common(searcher, revision)
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def heads(self, keys):
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"""Return the heads from amongst keys.
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This is done by searching the ancestries of each key. Any key that is
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reachable from another key is not returned; all the others are.
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This operation scales with the relative depth between any two keys. If
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any two keys are completely disconnected all ancestry of both sides
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:param keys: An iterable of keys.
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:return: A set of the heads. Note that as a set there is no ordering
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information. Callers will need to filter their input to create
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order if they need it.
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candidate_heads = set(keys)
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if len(candidate_heads) < 2:
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return candidate_heads
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searchers = dict((c, self._make_breadth_first_searcher([c]))
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for c in candidate_heads)
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active_searchers = dict(searchers)
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# skip over the actual candidate for each searcher
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for searcher in active_searchers.itervalues():
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while len(active_searchers) > 0:
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for candidate in active_searchers.keys():
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searcher = active_searchers[candidate]
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# rare case: we deleted candidate in a previous iteration
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# through this for loop, because it was determined to be
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# a descendant of another candidate.
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ancestors = searcher.next()
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except StopIteration:
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del active_searchers[candidate]
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for ancestor in ancestors:
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if ancestor in candidate_heads:
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candidate_heads.remove(ancestor)
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del searchers[ancestor]
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if ancestor in active_searchers:
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del active_searchers[ancestor]
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for searcher in searchers.itervalues():
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if ancestor not in searcher.seen:
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# if this revision was seen by all searchers, then it
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# is a descendant of all candidates, so we can stop
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# searching it, and any seen ancestors
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for searcher in searchers.itervalues():
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searcher.find_seen_ancestors(ancestor)
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searcher.stop_searching_any(seen_ancestors)
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return candidate_heads
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def find_unique_lca(self, left_revision, right_revision):
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"""Find a unique LCA.
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Find lowest common ancestors. If there is no unique common
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ancestor, find the lowest common ancestors of those ancestors.
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Iteration stops when a unique lowest common ancestor is found.
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The graph origin is necessarily a unique lowest common ancestor.
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Note that None is not an acceptable substitute for NULL_REVISION.
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in the input for this method.
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revisions = [left_revision, right_revision]
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lca = self.find_lca(*revisions)
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raise errors.NoCommonAncestor(left_revision, right_revision)
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def iter_topo_order(self, revisions):
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"""Iterate through the input revisions in topological order.
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This sorting only ensures that parents come before their children.
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An ancestor may sort after a descendant if the relationship is not
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visible in the supplied list of revisions.
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sorter = tsort.TopoSorter(zip(revisions, self.get_parents(revisions)))
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return sorter.iter_topo_order()
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def is_ancestor(self, candidate_ancestor, candidate_descendant):
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"""Determine whether a revision is an ancestor of another.
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There are two possible outcomes: True and False, but there are three
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possible relationships:
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a) candidate_ancestor is an ancestor of candidate_descendant
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b) candidate_ancestor is an descendant of candidate_descendant
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c) candidate_ancestor is an sibling of candidate_descendant
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To check for a, we walk from candidate_descendant, looking for
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To check for b, we walk from candidate_ancestor, looking for
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candidate_descendant.
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To make a and b more efficient, we can stop any searches that hit
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If we exhaust our searches, but neither a or b is true, then c is true.
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In order to find c efficiently, we must avoid searching from
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candidate_descendant or candidate_ancestor into common ancestors. But
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if we don't search common ancestors at all, we won't know if we hit
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common ancestors. So we have a walker for common ancestors. Note that
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its searches are not required to terminate in order to determine c to
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ancestor_walker = self._make_breadth_first_searcher(
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[candidate_ancestor])
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descendant_walker = self._make_breadth_first_searcher(
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[candidate_descendant])
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common_walker = self._make_breadth_first_searcher([])
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active_ancestor = True
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active_descendant = True
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while (active_ancestor or active_descendant):
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if active_descendant:
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nodes = descendant_walker.next()
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except StopIteration:
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active_descendant = False
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if candidate_ancestor in nodes:
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new_common.update(nodes.intersection(ancestor_walker.seen))
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nodes = ancestor_walker.next()
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except StopIteration:
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active_ancestor = False
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if candidate_descendant in nodes:
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new_common.update(nodes.intersection(
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descendant_walker.seen))
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new_common.update(common_walker.next())
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except StopIteration:
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for walker in (ancestor_walker, descendant_walker):
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for node in new_common:
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c_ancestors = walker.find_seen_ancestors(node)
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walker.stop_searching_any(c_ancestors)
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common_walker.start_searching(new_common)
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class _BreadthFirstSearcher(object):
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"""Parallel search the breadth-first the ancestry of revisions.
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This class implements the iterator protocol, but additionally
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1. provides a set of seen ancestors, and
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2. allows some ancestries to be unsearched, via stop_searching_any
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def __init__(self, revisions, parents_provider):
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self._start = set(revisions)
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self._search_revisions = None
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self.seen = set(revisions)
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self._parents_provider = parents_provider
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return ('_BreadthFirstSearcher(self._search_revisions=%r,'
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' self.seen=%r)' % (self._search_revisions, self.seen))
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"""Return the next ancestors of this revision.
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Ancestors are returned in the order they are seen in a breadth-first
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traversal. No ancestor will be returned more than once.
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if self._search_revisions is None:
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self._search_revisions = self._start
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new_search_revisions = set()
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for parents in self._parents_provider.get_parents(
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self._search_revisions):
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new_search_revisions.update(p for p in parents if
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self._search_revisions = new_search_revisions
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if len(self._search_revisions) == 0:
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raise StopIteration()
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self.seen.update(self._search_revisions)
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return self._search_revisions
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def find_seen_ancestors(self, revision):
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"""Find ancestors of this revision that have already been seen."""
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searcher = _BreadthFirstSearcher([revision], self._parents_provider)
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seen_ancestors = set()
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for ancestors in searcher:
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for ancestor in ancestors:
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if ancestor not in self.seen:
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searcher.stop_searching_any([ancestor])
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seen_ancestors.add(ancestor)
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return seen_ancestors
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def stop_searching_any(self, revisions):
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Remove any of the specified revisions from the search list.
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None of the specified revisions are required to be present in the
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search list. In this case, the call is a no-op.
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stopped = self._search_revisions.intersection(revisions)
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self._search_revisions = self._search_revisions.difference(revisions)
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def start_searching(self, revisions):
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if self._search_revisions is None:
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self._start = set(revisions)
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self._search_revisions.update(revisions.difference(self.seen))
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self.seen.update(revisions)
added
removed
bzrlib/graph.py
