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Viewing changes to bzrlib/tests/blackbox/test_pull.py

  • Committer: Aaron Bentley
  • Date: 2007-01-17 15:39:21 UTC
  • mfrom: (1551.9.35 Aaron's mergeable stuff)
  • mto: This revision was merged to the branch mainline in revision 2239.
  • Revision ID: abentley@panoramicfeedback.com-20070117153921-6pp9ssa2r8n5izoo
Merge bzr.ab, to avoid conflicts submitting

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bzrlib/tests/blackbox/test_pull.py
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# Copyright (C) 2005 by Canonical Ltd
 
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# Copyright (C) 2005 Canonical Ltd
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# -*- coding: utf-8 -*-
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA
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"""Black-box tests for bzr pull.
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"""
 
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"""Black-box tests for bzr pull."""
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import os
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import sys
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from bzrlib.branch import Branch
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from bzrlib.osutils import abspath
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from bzrlib.tests.blackbox import ExternalBase
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from bzrlib.uncommit import uncommit
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        self.runbzr('missing', retcode=3)
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        self.runbzr('missing .')
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        self.runbzr('missing')
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        if sys.platform not in ('win32', 'cygwin'):
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            # This is equivalent to doing "bzr pull ."
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            # Which means that bzr creates 2 branches grabbing
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            # the same location, and tries to pull.
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            # However, 2 branches mean 2 locks on the same file
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            # which ultimately implies a deadlock.
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            # (non windows platforms allow multiple locks on the
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            # same file by the same calling process)
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            self.runbzr('pull')
 
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        # this will work on windows because we check for the same branch
 
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        # in pull - if it fails, it is a regression
 
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        self.runbzr('pull')
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        self.runbzr('pull /', retcode=3)
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        if sys.platform not in ('win32', 'cygwin'):
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            self.runbzr('pull')
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        self.build_tree(['branch_a/a'])
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        tree_a.add('a')
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        tree_a.commit('commit a')
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        branch_b = branch_a.bzrdir.sprout('branch_b').open_branch()
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        tree_b = branch_b.bzrdir.open_workingtree()
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        branch_c = branch_a.bzrdir.sprout('branch_c').open_branch()
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        tree_c = branch_c.bzrdir.open_workingtree()
 
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        tree_b = branch_a.bzrdir.sprout('branch_b').open_workingtree()
 
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        branch_b = tree_b.branch
 
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        tree_c = branch_a.bzrdir.sprout('branch_c').open_workingtree()
 
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        branch_c = tree_c.branch
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        self.build_tree(['branch_a/b'])
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        tree_a.add('b')
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        tree_a.commit('commit b')
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        tree_b.commit('commit d')
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        out = self.runbzr('pull ../branch_a', retcode=3)
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        self.assertEquals(out,
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                ('','bzr: ERROR: These branches have diverged.  Try merge.\n'))
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        self.assertEquals(abspath(branch_b.get_parent()), abspath(parent))
 
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                ('','bzr: ERROR: These branches have diverged.  Use the merge command to reconcile them.\n'))
 
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        self.assertEquals(branch_b.get_parent(), parent)
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        # test implicit --remember after resolving previous failure
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        uncommit(branch=branch_b, tree=tree_b)
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        transport.delete('branch_b/d')
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        self.runbzr('pull')
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        self.assertEquals(abspath(branch_b.get_parent()), abspath(parent))
 
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        self.assertEquals(branch_b.get_parent(), parent)
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        # test explicit --remember
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        self.runbzr('pull ../branch_c --remember')
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        self.assertEquals(abspath(branch_b.get_parent()),
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                          abspath(branch_c.bzrdir.root_transport.base))
 
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        self.assertEquals(branch_b.get_parent(),
 
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                          branch_c.bzrdir.root_transport.base)
 
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    def test_pull_bundle(self):
 
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        from bzrlib.testament import Testament
 
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        # Build up 2 trees and prepare for a pull
 
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        tree_a = self.make_branch_and_tree('branch_a')
 
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        f = open('branch_a/a', 'wb')
 
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        f.write('hello')
 
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        f.close()
 
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        tree_a.add('a')
 
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        tree_a.commit('message')
 
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        tree_b = tree_a.bzrdir.sprout('branch_b').open_workingtree()
 
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        # Make a change to 'a' that 'b' can pull
 
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        f = open('branch_a/a', 'wb')
 
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        f.write('hey there')
 
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        f.close()
 
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        tree_a.commit('message')
 
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        # Create the bundle for 'b' to pull
 
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        os.chdir('branch_a')
 
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        bundle_file = open('../bundle', 'wb')
 
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        bundle_file.write(self.run_bzr('bundle', '../branch_b')[0])
 
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        bundle_file.close()
 
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        os.chdir('../branch_b')
 
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        output = self.run_bzr('pull', '../bundle')
 
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        self.assertEqual('', output[0])
 
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        self.assertEqual('All changes applied successfully.\n'
 
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                         '1 revision(s) pulled.\n', output[1])
 
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        self.assertEqualDiff(tree_a.branch.revision_history(),
 
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                             tree_b.branch.revision_history())
 
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        testament_a = Testament.from_revision(tree_a.branch.repository,
 
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                                              tree_a.get_parent_ids()[0])
 
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        testament_b = Testament.from_revision(tree_b.branch.repository,
 
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                                              tree_b.get_parent_ids()[0])
 
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        self.assertEqualDiff(testament_a.as_text(),
 
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                             testament_b.as_text())
 
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        # it is legal to attempt to pull an already-merged bundle
 
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        output = self.run_bzr('pull', '../bundle')
 
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        self.assertEqual('', output[0])
 
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        self.assertEqual('0 revision(s) pulled.\n', output[1])